Oh, the ask is a new one that I hadn't thought about before.
We cal also derive I the usual way with S and K, I = S K K = pure <*> pure, but that doesn't have any meaningful interpretation outside of the (->) r instance for Applicative.

The only use for that correspondence that I have seen is in the @pl extension of LambdaBot that transforms arbitrary haskell programs into point free style, by using combinators (including SKI).

Yeah - like, if you can efficiently translate LC to SKI (I'm reading http://okmij.org/ftp/tagless-final/ski.pdf BTW), then this is basically how you turn it into point-free

This correspondence is something I noticed a while ago while playing with ((->) r). I've written a small piece about it: https://pedrominicz.github.io/arrow

Is this "correspondence" useful or interesting in any way? (talking about SKI combinators):

(in context of

`Applicative (r ->)`

)Oh, the

`ask`

is a new one that I hadn't thought about before.We cal also derive

`I`

the usual way with`S`

and`K`

,`I = S K K = pure <*> pure`

, but that doesn't have any meaningful interpretation outside of the`(->) r`

instance for Applicative.The only use for that correspondence that I have seen is in the

`@pl`

extension of LambdaBot that transforms arbitrary haskell programs into point free style, by using combinators (including SKI).Yeah - like, if you can efficiently translate LC to SKI (I'm reading http://okmij.org/ftp/tagless-final/ski.pdf BTW), then this is basically how you turn it into point-free

I was recently reading this post, which mentions that it is the method LambdaBot uses: https://doisinkidney.com/posts/2020-10-17-ski.html

Ben Lynn has write about compiling lambda calculus to WASM by first translating it to SKI. http://www-cs-students.stanford.edu/~blynn/lambda/sk.html

This correspondence is something I noticed a while ago while playing with

`((->) r)`

. I've written a small piece about it: https://pedrominicz.github.io/arrowThe correspondence between

`ask`

and`id`

is very interesting. Hadn't noticed it before.